1000的阶乘的JAVA实现

package code;
 
public class SB {
 
    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub
 
        System.out.println();
        int[] a = get(1000);
        for (int i = 0; i < a.length; i++) {
            System.out.print(a[i]);
            if (i % 30 == 0)
                System.out.println();
        }
    }
 
    static int[] get(int n) {
        double a = 0;
        for (int j = 1; j < n; j++)
            a += Math.log10((double) j);
 
        int ab = (int) a;
        int[] aa = new int[ab+1];
        aa[ab] = 1;
        for (int j = 1; j <= n; j++) {
 
            for (int i = ab; i >=0; i--) {
                aa[i] = aa[i] * j;
 
            }
            for (int i = ab; i > 0; i--) {
                aa[i - 1] += aa[i] / 10;
                aa[i] = aa[i] % 10;
            }
        }
        return aa;
    }
 
}